Enough for an invite?
#2
Posted 2007-May-26, 15:27
Hannie, on May 26 2007, 04:16 PM, said:
p-(1H)-1S-(2H)
??
This is close but I would bid 2s, freebid, even at imps.
1) Partner has overcalled in the boss suit, spades nv, lets give her a break.
2) Qx of hearts looks like a downgrade
3) xxx of trumps looks like a downgrade
4) no stiff or void, flat shape looks like a downgrade.
5) K of D is neutral
6) Ace of clubs is a plus.
7) I think a free bid shows something, not random flat 5 HCP.
#3
Posted 2007-May-26, 15:58
Make the hearts a small doubleton and the diamonds KQxxx and I invite.
Peter
#4
Posted 2007-May-26, 16:15
Dbl is right on spot as to where our values are, but buries support if LHO bids. 2♠ is a slight distortion, but we can always dbl later to show a low ODR if the tactical situation calls for it.
2♠ it is.
#5
Posted 2007-May-26, 16:30
If your silly silly partner can't make 3♠ with this brilliant dummy, u have every right to tell him off!
George Carlin
#6
Posted 2007-May-26, 16:54
gwnn, on May 26 2007, 10:30 PM, said:
Your silly pard made a 3rd seat 1♠ overcall. He doesn't promise the world. In fact, 4 good spades is enough to make the bid.
#7
Posted 2007-May-26, 16:57
Pd will overcall 1S on AKJxx and out - even over 1H.
#8
Posted 2007-May-26, 16:59
#9 Guest_Jlall_*
Posted 2007-May-27, 02:30
#10
Posted 2007-May-27, 02:57
#11
Posted 2007-May-27, 10:13
- hrothgar
#12
Posted 2007-May-27, 10:41
Hannie, on May 27 2007, 11:13 AM, said:
Can you post partner's hand? I'm just curious.
#13
Posted 2007-May-27, 11:10
edit: I looked up the full hand:
p - 1H - 1S - 2H
2S - 3C - p - 3H
all pass
So 3SX isn't even a big disaster as the opponents can make 4H. Passing out 3H was better.
- hrothgar
#15
Posted 2007-May-27, 11:25
- hrothgar
#16
Posted 2007-May-27, 11:49
#17
Posted 2007-May-27, 13:39
But I'll still stick to my double by preference and 3H by necessity.
There are many situations like this that define the outcome of competition - you pay your money and take your place in the rankings.
#18
Posted 2007-May-29, 09:40
Jlall, on May 27 2007, 04:30 AM, said:
Agree.
p-(1H)-1S-(2H)
??